Pregunta
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\( \frac { 18 ^ { d } \cdot 15 ^ { a + 1 } } { 30 ^ { d - 1 } } \times \frac { ( 3 ^ { a } , 6 ) ^ { 2 } } { 9 ^ { a } - 1 } \div \frac { 36 ^ { a + 1 } } { 18 ^ { d - 1 } } \)

Ask by Vargas Newton. in South Africa
Mar 22,2025

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The simplified expression is \( \frac{2^{6-d+2a} \times 3^{8-d+5a} \times 5^{a+2-d}}{9^{a}-1} \).

Solución

Let's simplify the expression step by step: 1. **First Expression**: \( \frac { 18 ^ { d } \cdot 15 ^ { a + 1 } } { 30 ^ { d - 1 } } \) 2. **Second Expression**: \( \frac { ( 3 ^ { a } , 6 ) ^ { 2 } } { 9 ^ { a } - 1 } \) 3. **Third Expression**: \( \frac { 36 ^ { a + 1 } } { 18 ^ { d - 1 } } \) We will first simplify each part and then combine them according to the operations given (multiplication and division). ### Step 1: Simplifying Each Expression **First Expression**: \[ \frac { 18 ^ { d } \cdot 15 ^ { a + 1 } } { 30 ^ { d - 1 } } \] **Second Expression**: \[ \frac { ( 3 ^ { a } , 6 ) ^ { 2 } } { 9 ^ { a } - 1 } \] **Third Expression**: \[ \frac { 36 ^ { a + 1 } } { 18 ^ { d - 1 } } \] ### Step 2: Combine the Expressions The overall expression can be rewritten as: \[ \left( \frac { 18 ^ { d } \cdot 15 ^ { a + 1 } } { 30 ^ { d - 1 } } \times \frac { ( 3 ^ { a } , 6 ) ^ { 2 } } { 9 ^ { a } - 1 } \right) \div \frac { 36 ^ { a + 1 } } { 18 ^ { d - 1 } } \] This can be expressed as: \[ \left( \frac { 18 ^ { d } \cdot 15 ^ { a + 1 } \cdot ( 3 ^ { a } , 6 ) ^ { 2 } } { 30 ^ { d - 1 } \cdot ( 9 ^ { a } - 1 ) } \right) \cdot \frac { 18 ^ { d - 1 } } { 36 ^ { a + 1 } } \] Now, let's simplify this entire expression. ### Step 3: Perform the Simplification I will now perform the simplification of the entire expression. It seems that the expression is too complex for direct simplification in one step. Let's break it down further into manageable parts and simplify each part step by step. ### Step 1: Simplify Each Component 1. **First Expression**: \[ \frac { 18 ^ { d } \cdot 15 ^ { a + 1 } } { 30 ^ { d - 1 } } \] 2. **Second Expression**: \[ \frac { ( 3 ^ { a } , 6 ) ^ { 2 } } { 9 ^ { a } - 1 } \] 3. **Third Expression**: \[ \frac { 36 ^ { a + 1 } } { 18 ^ { d - 1 } } \] ### Step 2: Simplify Each Expression Individually #### First Expression Let's simplify \( \frac { 18 ^ { d } \cdot 15 ^ { a + 1 } } { 30 ^ { d - 1 } } \). #### Second Expression Next, we will simplify \( \frac { ( 3 ^ { a } , 6 ) ^ { 2 } } { 9 ^ { a } - 1 } \). #### Third Expression Finally, we will simplify \( \frac { 36 ^ { a + 1 } } { 18 ^ { d - 1 } } \). I will perform these simplifications one by one. Let's start with the first expression. Simplify the expression by following steps: - step0: Solution: \(\frac{18^{d}\times 15^{a+1}}{30^{d-1}}\) - step1: Factor the expression: \(\frac{6^{d}\times 3^{d}\times 15^{a+1}}{6^{d-1}\times 5^{d-1}}\) - step2: Reduce the fraction: \(\frac{6\times 3^{d}\times 15^{a+1}}{5^{d-1}}\) - step3: Simplify: \(\frac{6\times 3^{d+a+1}\times 5^{a+1}}{5^{d-1}}\) - step4: Reduce the fraction: \(6\times 3^{d+a+1}\times 5^{a+2-d}\) Calculate or simplify the expression \( (3^a * 6)^2 \). Simplify the expression by following steps: - step0: Solution: \(\left(3^{a}\times 6\right)^{2}\) - step1: Multiply the terms: \(\left(6\times 3^{a}\right)^{2}\) - step2: Evaluate the power: \(6^{2}\left(3^{a}\right)^{2}\) - step3: Evaluate the power: \(36\left(3^{a}\right)^{2}\) - step4: Evaluate the power: \(36\times 3^{2a}\) Calculate or simplify the expression \( 9^a - 1 \). Simplify the expression by following steps: - step0: Solution: \(9^{a}-1\) Calculate or simplify the expression \( \frac { 36^{a + 1} } { 18^{d - 1} } \). Simplify the expression by following steps: - step0: Solution: \(\frac{36^{a+1}}{18^{d-1}}\) - step1: Calculate: \(\frac{2^{3+2a}\times 9^{a+2}\times \frac{1}{18}}{18^{d}\times \frac{1}{18}}\) - step2: Reduce the fraction: \(\frac{2^{3+2a}\times 9^{a+2}}{18^{d}}\) Now that we have simplified each component, let's summarize the results: 1. **First Expression**: \[ \frac { 18 ^ { d } \cdot 15 ^ { a + 1 } } { 30 ^ { d - 1 } } = 6 \times 3^{d+a+1} \times 5^{a+2-d} \] 2. **Second Expression**: \[ \frac { ( 3 ^ { a } , 6 ) ^ { 2 } } { 9 ^ { a } - 1 } = \frac{36 \times 3^{2a}}{9^{a}-1} \] 3. **Third Expression**: \[ \frac { 36^{a + 1} } { 18^{d - 1} } = \frac{2^{3+2a} \times 9^{a+2}}{18^{d}} \] ### Step 3: Combine the Expressions Now we can combine these results into the overall expression: \[ \left( 6 \times 3^{d+a+1} \times 5^{a+2-d} \times \frac{36 \times 3^{2a}}{9^{a}-1} \right) \cdot \frac{2^{3+2a} \times 9^{a+2}}{18^{d}} \] ### Step 4: Simplify the Combined Expression Let's simplify this combined expression. I will perform the simplification now. Simplify the expression by following steps: - step0: Solution: \(\left(6\times 3^{d+a+1}\times 5^{a+2-d}\times \frac{36\times 3^{2a}}{9^{a}-1}\right)\times \frac{2^{3+2a}\times 9^{a+2}}{18^{d}}\) - step1: Remove the parentheses: \(6\times 3^{d+a+1}\times 5^{a+2-d}\times \frac{36\times 3^{2a}}{9^{a}-1}\times \frac{2^{3+2a}\times 9^{a+2}}{18^{d}}\) - step2: Multiply the terms: \(\frac{216\times 3^{d+3a+1}\times 5^{a+2-d}}{9^{a}-1}\times \frac{2^{3+2a}\times 9^{a+2}}{18^{d}}\) - step3: Rewrite the expression: \(\frac{216\times 3^{d+3a+1}\times 5^{a+2-d}}{9^{a}-1}\times \frac{2^{3+2a}\times 9^{a+2}}{3^{d}\times 6^{d}}\) - step4: Reduce the fraction: \(\frac{216\times 3^{3a+1}\times 5^{a+2-d}}{9^{a}-1}\times \frac{2^{3+2a}\times 9^{a+2}}{6^{d}}\) - step5: Multiply the terms: \(\frac{216\times 3^{3a+1}\times 5^{a+2-d}\times 2^{3+2a}\times 9^{a+2}}{\left(9^{a}-1\right)\times 6^{d}}\) - step6: Factor the expression: \(\frac{6^{3}\times 3^{3a+1}\times 5^{a+2-d}\times 2^{3+2a}\times 9^{a+2}}{\left(9^{a}-1\right)\times 6^{d}}\) - step7: Divide the numbers: \(\frac{6^{3-d}\times 3^{3a+1}\times 5^{a+2-d}\times 2^{3+2a}\times 9^{a+2}}{9^{a}-1}\) - step8: Simplify: \(\frac{2^{6-d+2a}\times 3^{8-d+5a}\times 5^{a+2-d}}{9^{a}-1}\) The final simplified expression is: \[ \frac{2^{6-d+2a} \times 3^{8-d+5a} \times 5^{a+2-d}}{9^{a}-1} \] This represents the result of the original expression you provided.

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Bonus Knowledge

To simplify the given expression, let's first rewrite each number as powers of their prime factorizations. 1. \( 18 = 2 \cdot 3^2 \) 2. \( 15 = 3 \cdot 5 \) 3. \( 30 = 2 \cdot 3 \cdot 5 \) 4. \( 9 = 3^2 \) 5. \( 36 = 2^2 \cdot 3^2 \) 6. \( 6 = 2 \cdot 3 \) Now substituting these values into the expression: \[ \frac{(2 \cdot 3^2)^{d} \cdot (3 \cdot 5)^{a + 1}}{(2 \cdot 3 \cdot 5)^{d - 1}} \times \frac{(3^{a}, 6)^{2}}{9^{a} - 1} \div \frac{(2^2 \cdot 3^2)^{a + 1}}{(2 \cdot 3^2)^{d - 1}} \] Starting with each part separately, we can simplify the exponents in the fractions and the products. For the denominator and the numerator: - **Numerator Simplification**: The first fraction becomes \( \frac{2^{d} \cdot 3^{2d} \cdot 3^{a + 1} \cdot 5^{a + 1}}{2^{d - 1} \cdot 3^{d - 1} \cdot 5^{d - 1}} \). - **Simplifying the Exponents**: \[ = \frac{2^{d - (d - 1)} \cdot 3^{2d + a + 1 - (d - 1)} \cdot 5^{a + 1 - (d - 1)}}{= 2^{1} \cdot 3^{3d + a + 2} \cdot 5^{a - d + 2}} \] - **Numerator of the second fraction** - since \( (3^{a}, 6)^{2} \) represents \( 3^{2a} 2^{2} \). - Numerator's second part becomes \( 3^{2a}/(9^{a} - 1)\). After substituting all this back into the original expression, extra simplification follows. Tackle each fraction and combine to get to a final fraction that can be further simplified, leading to the expression resolving to a simpler form. Finally, focus on dividing products, extending the simplifications and reducing common factors step by step to achieve a result in simplest form. Each exponent derived through careful multiplication and division leads us to our final structured exponentials in cleaner representation!

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