2) $$ \left[\begin{array}{ll}6 & -4\end{array} ight] \cdot\left[\begin{array}{cc}-3 & 3 \ -1 & -1\end{array} ight] $$

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2) $$ \left[\begin{array}{ll}6 & -4\end{array}ight] \cdot\left[\begin{array}{cc}-3 & 3 \ -1 & -1\end{array}ight] $$

UpStudy AI · Accepted Answer

We start with the matrix multiplication:

$$
\begin{bmatrix} 6 & -4 \end{bmatrix}
\cdot
\begin{bmatrix} -3 & 3 \ -1 & -1 \end{bmatrix}
$$

Since the first matrix is $$1 \times 2$$ and the second matrix is $$2 \times 2$$, the product will be a $$1 \times 2$$ matrix. The entries are computed as follows:

**First entry (column 1):**

$$
6 \cdot (-3) + (-4) \cdot (-1) = -18 + 4 = -14
$$

**Second entry (column 2):**

$$
6 \cdot 3 + (-4) \cdot (-1) = 18 + 4 = 22
$$

Thus, the resulting matrix is:

$$
\begin{bmatrix} -14 & 22 \end{bmatrix}
$$
The result of the matrix multiplication is $$[-14, 22]$$.

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