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A saturated solution is made by dissolving 36.8 g of a solid solute in 200 mL of water. A second solution is made by dissolving 20.3 g of the same solid solute in 100 mL of water. How would the second solution be classified? saturated hypersaturated supersaturated

Ask by Barker Byrd. in the United States
Feb 21,2025

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The second solution is classified as supersaturated.

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First, we determine the solubility from the saturated solution: 36.8 g of solute in 200 mL of water gives a concentration of 36.8 g/200 mL = 0.184 g/mL. Then, for the second solution, 20.3 g are dissolved in 100 mL of water, which gives a concentration of 20.3 g/100 mL = 0.203 g/mL. Since 0.203 g/mL is greater than 0.184 g/mL, the second solution contains more solute than what can normally be dissolved under saturation conditions. Therefore, the second solution is classified as supersaturated.

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To determine the classification of the second solution, we need to know the solubility of the solid solute at the given conditions. A saturated solution contains the maximum amount of solute that can dissolve in the solvent at a specific temperature. The first solution is saturated with 36.8 g in 200 mL, indicating that this amount of solute represents the solubility limit. For this case, this means that 18.4 g of solute (36.8 g / 2) could dissolve in 100 mL of water. Since the second solution only has 20.3 g of solute in 100 mL, it exceeds the saturation point, classifying it as supersaturated. In a nutshell, saturated solutions are like that perfect cup of coffee, containing just enough sugar to sweeten it up without going overboard. When a solution is supersaturated, it's like that ambitious friend who adds way too much sugar – they’ve pushed beyond what's normal, creating a concoction that's unstable and can easily crystallize back down to a sweet balance.

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