0.25 mole of Mg contains how many atoms? a 0.25 atoms b \( 1.51 \times 10^{23} \) atoms c \( 6.022 \times 10^{23} \) atoms d 1.51 atoms

To find the number of atoms in 0.25 moles of magnesium (Mg), you can use Avogadro's number, which is approximately \( 6.022 \times 10^{23} \) atoms per mole. By multiplying 0.25 moles by Avogadro's number, you get: \[ 0.25 \, \text{moles} \times 6.022 \times 10^{23} \, \text{atoms/mole} \approx 1.51 \times 10^{23} \, \text{atoms} \] So the correct answer is b \( 1.51 \times 10^{23} \) atoms. Understanding moles and the concept of Avogadro's number is essential for any chemistry enthusiast! Think of a mole as a "chemist’s dozen"—it's just a way to count particles like atoms. It makes the massive numbers in the atomic world manageable and helps chemists relate quantities on a more human scale. If you’re diving deeper into chemistry, mixing theoretical knowledge with practical applications is key! When you calculate moles in real-life scenarios, like in medication dosages or cooking recipes, these concepts help ensure accuracy. Imagine estimating the number of molecules in your favorite snack! Now, that's a tasty chemistry lesson.