Pregunta
127.51) \( \frac{32 r^{2} m^{3}}{16 r^{2} m^{-1}} \)
Ask by Owen Williams. in the United States
Mar 12,2025
Solución de inteligencia artificial de Upstudy
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The simplified form is \( 2m^{4} \).
Solución
Calculate or simplify the expression \( \frac{32r^{2}m^{3}}{16r^{2}m^{-1}} \).
Simplify the expression by following steps:
- step0: Solution:
\(\frac{32r^{2}m^{3}}{16r^{2}m^{-1}}\)
- step1: Reduce the fraction:
\(2m^{4}\)
The simplified form of the expression \( \frac{32r^{2}m^{3}}{16r^{2}m^{-1}} \) is \( 2m^{4} \).
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Simplifique esta solución The Deep Dive
To simplify \( \frac{32 r^{2} m^{3}}{16 r^{2} m^{-1}} \), first, observe that both the numerator and denominator have \( r^2 \). This cancels out, leading to: \[ \frac{32 m^{3}}{16 m^{-1}}. \] Next, simplify the numerical part: \( \frac{32}{16} = 2 \). Now focus on \( m^{3} \) and \( m^{-1} \). When dividing with the same base, you subtract the exponents: \[ m^{3 - (-1)} = m^{3 + 1} = m^{4}. \] Putting it all together: \[ 2 m^{4}. \] So, \[ \frac{32 r^{2} m^{3}}{16 r^{2} m^{-1}} = 2 m^{4}. \]
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