(b) \( \frac{5}{6}-\frac{2}{3}+\left(\frac{8}{9}\right) \)

To solve \( \frac{5}{6} - \frac{2}{3} + \frac{8}{9} \), we first need a common denominator, which is 18 in this case. First, convert each fraction: - \( \frac{5}{6} = \frac{5 \times 3}{6 \times 3} = \frac{15}{18} \) - \( \frac{2}{3} = \frac{2 \times 6}{3 \times 6} = \frac{12}{18} \) - \( \frac{8}{9} = \frac{8 \times 2}{9 \times 2} = \frac{16}{18} \) Now, substitute back into the equation: \[ \frac{15}{18} - \frac{12}{18} + \frac{16}{18} = \frac{15 - 12 + 16}{18} = \frac{19}{18} \] Thus, the final answer is \( \frac{19}{18} \) or \( 1 \frac{1}{18} \).