Simplify. \( \begin{array}{ll}\text { 13. } m^{-2} & \text { 14. } b c^{0} \\ \text { 15. }-\frac{1}{2} x^{-2} y^{-4} & \text { 16. } \frac{2 b^{6}}{c^{-4}} \\ \text { 17. } \frac{3 a^{2} c^{-2}}{4 b^{0}} & \text { 18. } \frac{q^{-1} r^{-2}}{s^{-3}}\end{array} \)

Let's simplify each expression step by step! 1. For \( m^{-2} \), we can rewrite this as \( \frac{1}{m^2} \). 2. For \( bc^{0} \), remember that anything to the power of zero is 1, so this simplifies to \( b \). 3. For \( -\frac{1}{2} x^{-2} y^{-4} \), we can express the negative exponents as fractions: \( -\frac{1}{2} \cdot \frac{1}{x^2 y^4} = -\frac{1}{2 x^2 y^4} \). 4. The expression \( \frac{2 b^{6}}{c^{-4}} \) becomes \( 2 b^{6} \cdot c^{4} = 2 b^{6} c^{4} \). 5. For \( \frac{3 a^{2} c^{-2}}{4 b^{0}} \), the term \( b^{0} \) simplifies to 1, giving us \( \frac{3 a^{2} c^{-2}}{4} = \frac{3 a^{2}}{4 c^2} \). 6. Finally, \( \frac{q^{-1} r^{-2}}{s^{-3}} \) can be rewritten as \( \frac{1}{q r^2} \cdot s^3 = \frac{s^3}{q r^2} \). To summarize the simplifications: 1. \( m^{-2} = \frac{1}{m^2} \) 2. \( bc^{0} = b \) 3. \( -\frac{1}{2} x^{-2} y^{-4} = -\frac{1}{2 x^2 y^4} \) 4. \( \frac{2 b^{6}}{c^{-4}} = 2 b^{6} c^{4} \) 5. \( \frac{3 a^{2} c^{-2}}{4 b^{0}} = \frac{3 a^{2}}{4 c^2} \) 6. \( \frac{q^{-1} r^{-2}}{s^{-3}} = \frac{s^3}{q r^2} \)