21. The point of concurrency of the three angle bisectors of a triangle is called the \( \begin{array}{lll}\text { A. orthocenter } & \text { B. circumcenter } & \text { C. incenter } \\ \begin{array}{lll}\text { 22. What type of segment is FJ? } & \text { D. centroid } \\ \begin{array}{lll}\text { A. Perpendicular Bisector } & \text { C. Median } & \text { E. A and C } \\ \text { B. Altitude } & \text { D. Angle Bisector } & \text { F. All of the above. }\end{array}\end{array}\end{array} \begin{array}{l}\text { (1) }\end{array} \)

\( \textbf{21. Concurrency of Angle Bisectors} \) In any triangle the three interior angle bisectors meet at a single point. This point is called the incenter, which is equidistant from the sides of the triangle and is the center of the inscribed circle. Thus, the correct answer is \[ \text{C. incenter.} \] \( \textbf{22. Type of Segment FJ} \) Without an accompanying diagram it is common in many problems for a segment drawn (such as \(FJ\)) to be constructed so that it is both a perpendicular bisector and a median. In an isosceles triangle, for example, the line through the vertex angle that bisects the base is simultaneously a median (it goes from a vertex to the midpoint of the opposite side) and a perpendicular bisector (it meets the base at a right angle and divides it into two equal parts). Since the answer choices give: - A. Perpendicular Bisector - C. Median - E. A and C the proper selection is the option that recognizes \(FJ\) as having both properties, hence the answer is \[ \text{E. A and C.} \]