What value of \( a \) will make the solution to the following equation be \( a x+5=35 \)

To solve for \( a \), we first simplify the equation \( a x + 5 = 35 \). By subtracting 5 from both sides, we get \( a x = 30 \). Now, to isolate \( a \), we need to express \( x \) in terms of \( a \). Thus, \( a = \frac{30}{x} \). The value of \( a \) depends on the value of \( x \), so any non-zero \( x \) will give a specific value for \( a \). If you want a specific example, let's say \( x = 2 \). Plugging it in, we find \( a = \frac{30}{2} = 15 \). So, the value of \( a \) can change based on the chosen value of \( x \).