A population of interest has a proportion of \( p=0.64 \). Consider a sampling distribution of the sample proportions for 1000 samples of sample size \( n=160 \). You may use the Sampling Distribution tool to answer the following. What value should be in the center of the distribution? 1000 160 0.64 102.4

The center of the sampling distribution of the sample proportions is determined by the population proportion \( p \). In this case, since the population proportion is \( p = 0.64 \), this is the value that will be at the center of the distribution. Now, when you multiply this proportion by the sample size \( n = 160 \), you can derive the expected number of successes in your sample. So, \( n \cdot p = 160 \cdot 0.64 = 102.4 \). However, the question specifically asks for the value at the center of the distribution, which would be simply \( 0.64 \). So the correct answer to the question is \( 0.64 \).