1. Calculate the a. 6 is \( 24 \% \) of a number, what is the number? b. If Birr 700 is \( 35 \% \) of Birr \( x \), then what is the value of \( x \) ? c. If \( 15 \% \) of a number is 18 , then what is the number? d. \( 40 \% \) of a number is 110 , what is number? 2. If \( 30 \% \) of a man's salary is Birr 6300 , what is the amount of his full salary? 3. In a class where the number of boys is \( 36 \% \) of the total number of student there are 18 boys, then how many students are there in the class?
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Bonus Knowledge
To find the number that corresponds to \( 6 \) being \( 24\% \), you can set up the equation \( 6 = 0.24x \). Solving gives \( x = \frac{6}{0.24} = 25 \). For the \( Birr 700 \), \( 700 = 0.35x \) leads to \( x = \frac{700}{0.35} = 2000 \). For \( 15\% \) giving \( 18 \), you solve \( 0.15x = 18 \) to find \( x = \frac{18}{0.15} = 120 \). Finally, with \( 40\% \) and \( 110 \), it's \( 0.40x = 110 \) which gives \( x = \frac{110}{0.40} = 275 \). For the man’s salary, if \( 30\% \) is \( 6300 \), set \( 6300 = 0.30s \) and find \( s = \frac{6300}{0.30} = 21000 \). Lastly, knowing \( 36\% \) of the total students equals \( 18 \), use \( 0.36t = 18 \) to find \( t = \frac{18}{0.36} = 50 \). So, the class has \( 50 \) students in total! Isn’t math magical?
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