Find the negatives (the additive inverses) of the given rational numbers. Show each number and its negative on the number line. \( \begin{array}{llll}\text { (a) } \frac{2}{5} & \text { (b) } \frac{-3}{2} & \text { (c) } \frac{8}{-3} & \text { (d) } \frac{8}{2}\end{array} \) (a) The additive inverse of \( \frac{2}{5} \) is

(a) The additive inverse of \( \frac{2}{5} \) is \( -\frac{2}{5} \). On the number line, \( \frac{2}{5} \) is located to the right of zero, while \( -\frac{2}{5} \) is positioned to the left, demonstrating how they balance each other out at the origin. (b) The additive inverse of \( \frac{-3}{2} \) is \( \frac{3}{2} \). On the number line, you’ll find \( \frac{-3}{2} \) on the left side, while \( \frac{3}{2} \) sits on the right side, perfectly representing the idea that one number negates the other, bringing them back to zero when combined!