Solve the quadratic equation. \[ x^{2}-x-10=0 \] Write one exact solution in each box. You can add or remove boxes. If there are no real solutions, remove all boxes.

To solve the quadratic equation \( x^{2}-x-10=0 \), we can use the quadratic formula: \[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \] Here, \( a = 1 \), \( b = -1 \), and \( c = -10 \). Calculating the discriminant: \[ b^2 - 4ac = (-1)^2 - 4(1)(-10) = 1 + 40 = 41 \] Now we plug the values into the quadratic formula: \[ x = \frac{-(-1) \pm \sqrt{41}}{2(1)} = \frac{1 \pm \sqrt{41}}{2} \] So the solutions are: \[ x_1 = \frac{1 + \sqrt{41}}{2} \] \[ x_2 = \frac{1 - \sqrt{41}}{2} \] Here are the exact solutions: **Box 1:** \( \frac{1 + \sqrt{41}}{2} \) **Box 2:** \( \frac{1 - \sqrt{41}}{2} \)