Divide. \[ \left(10 x^{2}+35 x+25\right) \div(2 x+5) \] Your answer should give the quotient and the remainder. Quotient: \( \square \) Remainder: \( \square \)

\[ \text{Step 1: Divide the leading term of the dividend by the leading term of the divisor: } \quad \frac{10x^2}{2x} = 5x. \] \[ \text{Step 2: Multiply the divisor by } 5x: \quad 5x \times (2x+5) = 10x^2+25x. \] \[ \text{Step 3: Subtract this product from the original polynomial: } \] \[ (10x^2+35x+25) - (10x^2+25x) = 10x+25. \] \[ \text{Step 4: Divide the new leading term by the leading term of the divisor: } \quad \frac{10x}{2x} = 5. \] \[ \text{Step 5: Multiply the divisor by } 5: \quad 5 \times (2x+5) = 10x+25. \] \[ \text{Step 6: Subtract this product: } \] \[ (10x+25) - (10x+25) = 0. \] \[ \text{Since the remainder is } 0\text{, the division is exact.} \] Quotient: \( 5x+5 \) Remainder: \( 0 \)