Uranium hexafluoride can leech into the air by bonding to water vapor to form $$ \mathrm{UO}_{2} \mathrm{~F}_{2} $$ and HF , both of which are toxic to humans. Which of the following describes this reaction? Choose 1 answer: (A) $$ \mathrm{UF}_{6}+2 \mathrm{H}_{2} \mathrm{O} \rightarrow \mathrm{UO}_{2} \mathrm{~F}_{2}+4 \mathrm{HF} $$ (B) $$ \mathrm{UF}_{6}+\mathrm{H}_{2} \mathrm{O} \rightarrow \mathrm{UO}_{2} \mathrm{~F}_{2}+2 \mathrm{HF} $$ (C) $$ \mathrm{UF}_{6}+4 \mathrm{H}_{2} \mathrm{O} \rightarrow \mathrm{UO}_{2} \mathrm{~F}_{2}+\mathrm{HF} $$ (D) $$ \mathrm{UF}_{6}+2 \mathrm{H}_{2} \mathrm{O} \rightarrow 3 \mathrm{UO}_{2} \mathrm{~F}_{2}+\mathrm{HF} $$

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UpStudy AI · Accepted Answer

To determine which reaction is balanced, we can check the atoms on both sides of each equation.

Let's analyze option (A):

Reaction (A): UF₆ + 2 H₂O → UO₂F₂ + 4 HF

Count atoms on the left:
• U: 1
• F: 6
• H: 2 × 2 = 4
• O: 2

Count atoms on the right:
• U: 1
• For UO₂F₂: U = 1, O = 2, F = 2
• For 4 HF: F = 4, H = 4
• Total F: 2 (from UO₂F₂) + 4 (from HF) = 6
• Total H: 4
• Total O: 2

Since all atoms balance, the reaction is correctly written.

Thus, the answer is (A):

UF₆ + 2 H₂O → UO₂F₂ + 4 HF
The correct reaction is: $$ \mathrm{UF}_{6} + 2 \mathrm{H}_{2} \mathrm{O} \rightarrow \mathrm{UO}_{2} \mathrm{~F}_{2} + 4 \mathrm{HF} $$

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