Watch the video and then solve the problem given below. Click here to watch the video. Find \( f(g(x)) \) and \( g(f(x)) \) and determine whether the pair of functions \( f \) and \( g \) are inverses of each other. \( f\left(x+1\right. \) and \( g(x)=\frac{x-1}{3} \) a. \( f(g(x))=x \) (Simplify your answer.) b. \( g(f(x))=x \) (Simplify your answer.) c. Are \( f \) and \( g \) inverses of each other? Yes No
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To find \( f(g(x)) \) and \( g(f(x)) \): 1. First, calculate \( f(g(x)) \): Given \( f(x) = x + 1 \) and \( g(x) = \frac{x - 1}{3} \), we start by substituting \( g(x) \) into \( f \): \[ f(g(x)) = f\left(\frac{x - 1}{3}\right) = \frac{x - 1}{3} + 1 = \frac{x - 1 + 3}{3} = \frac{x + 2}{3} \] 2. Now, calculate \( g(f(x)) \): Using the same functions, substitute \( f(x) \) into \( g \): \[ g(f(x)) = g(x + 1) = \frac{(x + 1) - 1}{3} = \frac{x}{3} \] 3. To determine if \( f \) and \( g \) are inverses, we check: - From our results: \( f(g(x)) = \frac{x + 2}{3} \) and \( g(f(x)) = \frac{x}{3} \). - Since neither \( f(g(x)) \) nor \( g(f(x)) \) simplifies to \( x \), we conclude that they are **not** inverses of each other. So the answers are: a. \( f(g(x)) = \frac{x + 2}{3} \) b. \( g(f(x)) = \frac{x}{3} \) c. Are \( f \) and \( g \) inverses of each other? **No**
