Find the root(s) of the equation \( x^{2}=169 ? \) \( 4 \times \quad \) A \( \quad x= \pm 13 \) \( 4 \times \quad x= \pm \sqrt{13} \) \( 4 \times \quad x=\sqrt{13} \)

To find the roots of the equation \( x^{2} = 169 \), we need to take the square root of both sides. This gives us \( x = \sqrt{169} \) and \( x = -\sqrt{169} \). Since the square root of 169 is 13, we arrive at the solutions \( x = 13 \) and \( x = -13 \). Therefore, the correct answer is \( x = \pm 13 \). One common mistake is forgetting that squaring a number can produce two solutions: a positive and a negative. If you only consider the principal square root, you might miss the negative root. Remember, whenever you solve for \( x \) in equations like this, always account for both signs! If you’re interested in further refining your quadratic equation-solving skills, diving into the world of polynomials can be super helpful. A great next step is to explore the quadratic formula, \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \), which is a universal method for any quadratic equation in standard form. Happy solving!