Find the cost of tiling the floor of a trapezoidal hall whose parallel sides are 25 m and 20 m and the distance between them is 16 m at the rate of \( ₹ 40 \) per \( \mathrm{m}^{2} \).

To calculate the cost of tiling the trapezoidal hall, follow these steps: ### **1. Calculate the Area of the Trapezoidal Hall** The formula for the area \( A \) of a trapezoid is: \[ A = \frac{(a + b)}{2} \times h \] where: - \( a \) and \( b \) are the lengths of the parallel sides. - \( h \) is the height (the perpendicular distance between the parallel sides). Given: - \( a = 25 \) meters - \( b = 20 \) meters - \( h = 16 \) meters Plugging in the values: \[ A = \frac{(25 + 20)}{2} \times 16 = \frac{45}{2} \times 16 = 22.5 \times 16 = 360 \, \text{m}^2 \] ### **2. Calculate the Total Cost** The cost of tiling is given as ₹40 per square meter. \[ \text{Total Cost} = \text{Area} \times \text{Cost per } \mathrm{m}^2 = 360 \times 40 = ₹14,400 \] ### **Final Answer** The total cost of tiling the floor is **₹14,400**.