Pregunta
BLAST FROM THE PAST Simplify each expression. 1.) \( w^{4} \cdot w^{6}= \) \( \qquad \) 24 2.) \( \left(8^{5}\right)^{3}= \) \( \qquad \) \( \lambda \) 3.) \( n^{3} \cdot n^{4}= \) \( \qquad \) 0.75 4.) \( 2 m^{6} \cdot 5 m^{3}= \) \( \qquad \) \( 10^{2} \) 5.) \( \frac{x^{4}}{x^{4}}= \) \( \qquad \) \( \frac{16}{6} \) 6.) \( \left[\left(7^{3}\right)^{2}\right]^{5}= \) \( \qquad \) 3 7.) \( \frac{4^{8}}{4^{6}}= \) \( \qquad \) \( \frac{2.5}{1.5} \) 8.) \( 6^{12} \cdot 6^{3}=36 \)
Ask by Davison Watkins. in the United States
Mar 20,2025
Solución de inteligencia artificial de Upstudy
Respuesta verificada por el tutor
Responder
1.) \( w^{10} \)
2.) \( 8^{15} \)
3.) \( n^{7} \)
4.) \( 10 m^{9} \)
5.) \( 1 \)
6.) \( 7^{30} \)
7.) \( 16 \)
8.) \( 6^{15} \)
Solución
1.) \( w^{4} \cdot w^{6} \)
Using the law of exponents for multiplication, add the exponents:
\( w^{4} \cdot w^{6} = w^{4+6} = w^{10} \).
2.) \( \left(8^{5}\right)^{3} \)
Raise a power to a power by multiplying exponents:
\( \left(8^{5}\right)^{3} = 8^{5\cdot3} = 8^{15} \).
(Alternatively, express \(8\) as \(2^3\) to get:
\( 8^{15} = \left(2^{3}\right)^{15} = 2^{45} \).)
3.) \( n^{3} \cdot n^{4} \)
Add the exponents when multiplying like bases:
\( n^{3} \cdot n^{4} = n^{3+4} = n^{7} \).
4.) \( 2 m^{6} \cdot 5 m^{3} \)
Group the numerical coefficients and the powers of \(m\):
\( 2 \cdot 5 = 10 \) and \( m^{6} \cdot m^{3} = m^{6+3} = m^{9} \).
Thus, \( 2 m^{6} \cdot 5 m^{3} = 10 m^{9} \).
5.) \( \frac{x^{4}}{x^{4}} \)
Subtract the exponents in the quotient (or note that any nonzero number divided by itself equals 1):
\( \frac{x^{4}}{x^{4}} = x^{4-4} = x^{0} = 1 \) (for \( x\neq0 \)).
6.) \( \left[\left(7^{3}\right)^{2}\right]^{5} \)
Multiply the exponents sequentially:
First, \( \left(7^{3}\right)^{2} = 7^{3\cdot2} = 7^{6} \).
Then, \( \left(7^{6}\right)^{5} = 7^{6\cdot5} = 7^{30} \).
7.) \( \frac{4^{8}}{4^{6}} \)
Subtract the exponents when dividing like bases:
\( \frac{4^{8}}{4^{6}} = 4^{8-6} = 4^{2} = 16 \).
8.) \( 6^{12} \cdot 6^{3} \)
Add the exponents when multiplying like bases:
\( 6^{12} \cdot 6^{3} = 6^{12+3} = 6^{15} \).
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Extra Insights
When you multiply expressions with the same base, you simply add their exponents! So for \( w^{4} \cdot w^{6} \), the result is \( w^{10} \). The bases combine seamlessly, just like how friends come together for a fun adventure. Exponents can sometimes seem like a tricky puzzle, but there’s a nifty rule: \( (a^{m})^{n} = a^{m \cdot n} \). So for \( \left(8^{5}\right)^{3} \), you multiply the exponents and get \( 8^{15} \). It's like stacking up cookies – the more levels, the sweeter the treat!
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