Suppose that the function \( g \) is defined, for all real numbers, as follows. \[ g(x)=\left\{\begin{array}{ll}-2 & \text { if } x<-2 \\ (x+1)^{2}-3 & \text { if }-2 \leq x<1 \\ \frac{1}{2} x+1 & \text { if } x \geq 1 \\ \text { Find } g(-4), g(0) \text {, and } g(1) \\ g(0)=-2\end{array}\right. \] \( g(1)=\square \)

To find \( g(-4) \), \( g(0) \), and \( g(1) \), let's evaluate each input according to the function definition. 1. For \( g(-4) \): Since \(-4 < -2\), we use the first piece of the function: \[ g(-4) = -2. \] 2. For \( g(0) \): Since \(0\) is in the interval \(-2 \leq x < 1\), we use the second piece of the function: \[ g(0) = (0 + 1)^{2} - 3 = 1 - 3 = -2. \] 3. For \( g(1) \): Since \(1 \geq 1\), we use the third piece of the function: \[ g(1) = \frac{1}{2} \cdot 1 + 1 = \frac{1}{2} + 1 = \frac{3}{2}. \] Thus, the values are: - \( g(-4) = -2 \) - \( g(0) = -2 \) - \( g(1) = \frac{3}{2} \) Therefore, \( g(1) = \frac{3}{2} \).