\( 12 h>36 \), if \( h=3 \)

Let's see what happens when we plug in \( h = 3 \) into the inequality \( 12h > 36 \). When you substitute, you get \( 12 \times 3 > 36 \) or \( 36 > 36 \). Oops! That’s not quite right, is it? Instead, it should be \( 36 > 36 \), which means that the inequality does not hold true; they are equal. So, when \( h = 3 \), that side of the inequality doesn’t satisfy the \( > \) condition! Now, let's take a look at the inequality more broadly. To satisfy \( 12h > 36 \), you would actually need \( h \) to be greater than \( 3 \) (since \( h > 3 \)). This means \( h \) can be any number like \( 4, 5, \) or even \( 10 \), and the inequality will hold true! Who knew that a little number crunching could lead to such a discovering?