Find the product. \( \frac{x+5}{x^{3}-1} \cdot\left(x^{2}+x+1\right)=\square \)
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To find the product \( \frac{x+5}{x^{3}-1} \cdot\left(x^{2}+x+1\right) \), we first note that \( x^3 - 1 \) can be factored using the identity for the difference of cubes: \[ x^3 - 1 = (x - 1)(x^2 + x + 1) \] Now, substituting this factorization into the expression, we have: \[ \frac{x+5}{(x - 1)(x^2 + x + 1)} \cdot (x^2 + x + 1) \] The \( x^2 + x + 1 \) terms will cancel out, assuming \( x^2 + x + 1 \neq 0 \) (which is valid for \( x \neq 1 \)). So, the expression simplifies to: \[ \frac{x+5}{x-1} \] Thus, the final answer is: \[ \frac{x+5}{x-1} \]
