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titative Literacy Hannah thompson 03/20/25 9:18 awork Question 7, 11,4.18 Part 5 of 8 HW Score: \( 58.33 \%, 6.83 \) of 10 points Points: 0 of 1 At a homeowners' association meeting, a board member can vote yes, vote no, or abstain on a motion. There are three motions on which each board member must vote. Complete parts (e) below. Click here to view tree diagram D Click here to view tree diagram C Click here to view tree diagram À Click here to view tree diagram B Determine the sample space. A. \( Y Y, Y N, Y A, N Y, N N, N A, A Y, A N, A A \) B. \( M Y, Y N, Y Y A, Y N Y, Y N N, Y N A, Y A Y, Y A N, Y A A, N Y Y, N Y N, N Y A, N N Y, N N N, N N A, N A Y, N A N, N A A, A Y Y, A Y N, A Y A, A N Y, A N N, A N A, A A Y, A A N, A A A \) C. \( \begin{array}{l} \\ Y\end{array}, Y Y, Y Y A, N N A, Y N N, Y N A, Y A Y, N A N, Y A A, N Y Y, N Y N, N A A, N N Y, N N N, A Y Y, A Y A, A N N, A N A, A A Y, A A A \) D. YN,YA,NY,NA,AY,AN c) Determine the probability that a board member votes abstain, no, yes in that order of the motions. \( \square \) \( \frac{1}{27} \) (Type an integet or a simplified fraction.) d) Determine the probability that a board member votes yes on exactly one of the motions. \( \square \) (Type an integer or a simplified fraction.)

Ask by Blake Chan. in the United States
Mar 21,2025

Solución de inteligencia artificial de Upstudy

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**Sample Space:** A. \( Y Y, Y N, Y A, N Y, N N, N A, A Y, A N, A A \) **Probability of Voting Abstain, No, Yes in Order:** \(\frac{1}{27}\) **Probability of Voting Yes on Exactly One Motion:** \(\frac{4}{9}\)

Solución

**Step 1. Determine the total number of outcomes in the sample space.** Each board member votes on 3 motions, and for each motion there are 3 choices: yes, no, or abstain. Therefore, the total number of outcomes is \[ 3^3 = 27. \] **Step 2. Part (c): Probability of voting abstain, no, yes in order.** For the first motion, the vote must be abstain; for the second, no; and for the third, yes. There is exactly 1 outcome that matches this specific sequence. Thus, the probability is \[ \frac{1}{27}. \] **Step 3. Part (d): Probability of voting yes on exactly one motion.** - First, choose which one of the 3 motions will have a yes vote. There are \[ \binom{3}{1} = 3 \text{ ways.} \] - For the remaining 2 motions, each vote can be either no or abstain (2 options for each motion). Therefore, there are \[ 2 \times 2 = 4 \text{ outcomes for the other motions.} \] - Thus, the total number of outcomes with exactly one yes vote is \[ 3 \times 4 = 12. \] The probability of exactly one yes vote is then \[ \frac{12}{27} = \frac{4}{9}. \] **Final Answers:** c) \(\frac{1}{27}\) d) \(\frac{4}{9}\)

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In this scenario, each board member has three choices (Yes, No, or Abstain) for each of the three motions. This setup creates a total of \(3^3 = 27\) possible outcomes. Therefore, the sample space consists of all combinations of votes for these three motions, such as \(YYY, YYN, YYA, YNY, YNA, \ldots, AAA\). The correct answer for the sample space is option A. Now, when calculating the probability that a board member votes in the specific order of Abstain, No, Yes (A, N, Y), we recognize that each choice is independent. Since there are 27 total outcomes and only one specific sequence matches this combination, the probability is \( \frac{1}{27} \). To find the probability that a board member votes yes on exactly one of the motions, you can consider the scenarios where they vote Yes in one motion and No or Abstain in the other two. Specifically, the combinations are: \(YNN, YNA, YAN, AYN, NAY\). Each counts as a favorable outcome, and since there are a total of 9 ways (3 motions to vote Yes, with 2 choices for the remaining votes), the probability is \( \frac{9}{27} = \frac{1}{3} \). Happy calculating!

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