2.- (N) A box contains Jolly Rancners. - 8 are blue raspberry - 8 are watermelon A Jolly Rancher is randomly drawn from the bag and eaten, then another one is drawn. What is the probability that the first Jolly Rancher will be a watermelon and the second Jolly Rancher will be cherry?

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UpStudy AI · Accepted Answer

Let's denote the given facts:

- Total Jolly Ranchers in the bag: $$ 8 \text{ (blue raspberry)} + 8 \text{ (watermelon)} = 16 $$.
- The flavors mentioned in the bag are blue raspberry and watermelon.
- No cherry Jolly Ranchers are present.

The problem asks for the probability that the first candy drawn is watermelon and the second candy drawn is cherry.

Step 1: Compute the probability that the first candy is watermelon.

$$
P(\text{first is watermelon}) = \frac{8}{16} = \frac{1}{2}
$$

Step 2: After one Jolly Rancher is eaten, there are 15 candies left. However, since there are no cherry Jolly Ranchers in the bag, the probability of drawing a cherry is

$$
P(\text{second is cherry}) = \frac{0}{15} = 0
$$

Step 3: Multiply the probabilities (noting that for successive independent or conditional events, we multiply the probabilities):

$$
P(\text{first is watermelon and second is cherry}) = \frac{1}{2} \times 0 = 0
$$

Thus, the probability that the first Jolly Rancher is watermelon and the second is cherry is $$ 0 $$.
The probability of drawing a watermelon first and a cherry second is 0.

2.- (N) A box contains Jolly Rancners. - 8 are blue raspberry - 8 are watermelon A Jolly Rancher is randomly drawn from the bag and eaten, then another one is drawn. What is the probability that the first Jolly Rancher will be a watermelon and the second Jolly Rancher will be cherry?

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