A tent is shaped like a triangular prism. Each end of the tent is an equilateral triangle with side length 4 feet. The tent is 9 feet long. Determine the surface area of the tent, not including the bottom.
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To find the surface area of the tent, we first calculate the area of the two triangular ends. For an equilateral triangle with side length \( s = 4 \) feet, the area \( A \) can be calculated using the formula: \[ A = \frac{\sqrt{3}}{4} s^2 = \frac{\sqrt{3}}{4} (4)^2 = \frac{\sqrt{3}}{4} \times 16 = 4\sqrt{3} \text{ square feet} \] Since there are two triangular ends, their combined area is: \[ 2 \times 4\sqrt{3} = 8\sqrt{3} \text{ square feet} \] Next, we calculate the area of the three rectangular sides. The length of the tent is 9 feet, and the height of each rectangle (the height of the triangular end) needs to be found. The height \( h \) of an equilateral triangle can be calculated as follows: \[ h = \frac{\sqrt{3}}{2} s = \frac{\sqrt{3}}{2} \times 4 = 2\sqrt{3} \text{ feet} \] The areas of the three rectangles are: 1. Two rectangles with dimensions \( 9 \) feet by \( 4 \) feet (the base of the triangular ends): \[ A_1 = 2 \times (9 \times 4) = 2 \times 36 = 72 \text{ square feet} \] 2. One rectangle with dimensions \( 9 \) feet by \( 2\sqrt{3} \) feet (the height of the triangular ends): \[ A_2 = 9 \times 2\sqrt{3} = 18\sqrt{3} \text{ square feet} \] Now add all the areas together to find the total surface area: \[ \text{Total Surface Area} = A_{\text{triangles}} + A_{\text{rectangles}} = 8\sqrt{3} + 72 + 18\sqrt{3} \] Combining the \( \sqrt{3} \) terms: \[ = (8\sqrt{3} + 18\sqrt{3}) + 72 = 26\sqrt{3} + 72 \text{ square feet} \] Thus, the surface area of the tent, not including the bottom, is: \[ \boxed{26\sqrt{3} + 72} \text{ square feet} \]
