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What is the prime factorization of 750 ?

Ask by Chambers Watkins. in the United States
Feb 28,2025

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The prime factorization of 750 is 2 × 3 × 5³.

Solución

To find the prime factorization of 750, follow these steps: 1. Since 750 is even, divide it by 2: 750 ÷ 2 = 375 Thus, 750 = 2 × 375. 2. Next, check divisibility of 375 by 3. The sum of its digits (3 + 7 + 5 = 15) is divisible by 3, so 375 is divisible by 3: 375 ÷ 3 = 125 Now, 750 = 2 × 3 × 125. 3. Finally, note that 125 is a power of 5: 125 = 5 × 5 × 5 = 5³ Therefore, 750 = 2 × 3 × 5³. The prime factorization of 750 is: 2 × 3 × 5³.

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The Deep Dive

The prime factorization of 750 begins with dividing by the smallest prime number, which is 2. Dividing 750 by 2 gives us 375. Next, we factor 375 by dividing it by 3 (the next smallest prime), resulting in 125. Finally, 125 can be divided by 5 repeatedly until we reach 1, giving us 5 × 5 × 5. So, the prime factorization of 750 is 2 × 3 × 5^3. To visualize this, you can think of prime factorization as a treasure hunt where you are breaking down a number into its most valuable pieces—the primes! It helps you understand the building blocks of numbers and has applications in everything from cryptography to simplifying fractions. Plus, once you get the hang of it, it's like unlocking secrets in math!

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