Check if this value of \( x \) satisfies the given equation. Substitute \( x=-\frac{10}{5} \) \[ \begin{array}{r}5 x=-10 \\ 5 \cdot \square=-10\end{array} \]

Let’s substitute \( x = -\frac{10}{5} \) which simplifies to \( x = -2 \). Now, we'll plug it into the equation. Calculating: \[ 5 \cdot (-2) = -10 \] Since \( -10 \) equals \( -10 \), this value of \( x \) indeed satisfies the equation. Now, it's great to know that substituting values is like testing out a key to see if it fits in a lock. You wouldn’t want to force it; instead, you check for that smooth turn! Also, remember that algebra isn't just about finding answers; it's about understanding the relationships between numbers. As you play around with different values, you build that intuitive sense that makes math feel less like a chore and more like a game!