Seniar 4 students of Sayidina Abubakar Secondory school
heaked a given mass of limestone under normal room condkions. The
limestane onder decomposed as according ko the following

They collected the gaseous product crolved using various gas syringes.
The gaseous product was found to be occupying a Totat volume of 6 lites
Although the students know that 1 mole of gas contains particles,
they are finding it hard to know the quantity of particles in gaseous produr
they had collecked.
Mask
a) Explain the categories of substances involved in the decom position

Determine the quality of parkicles in the gaseous produrt.

Ask by Gough Fernandez. in Uganda

Mar 29,2025

Question

Seniar 4 students of Sayidina Abubakar Secondory school
heaked a given mass of limestone under normal room condkions. The
limestane onder decomposed as according ko the following

They collected the gaseous product crolved using various gas syringes.
The gaseous product was found to be occupying a Totat volume of 6 lites
Although the students know that 1 mole of gas contains particles,
they are finding it hard to know the quantity of particles in gaseous produr
they had collecked.
Mask
a) Explain the categories of substances involved in the decom position

Determine the quality of parkicles in the gaseous produrt.

Ask by Gough Fernandez. in Uganda

Mar 29,2025

UpStudy AI · Accepted Answer

**Step 1. Categories of Substances Involved**

- $$ \mathrm{CaCO_3} $$ (limestone) is a **pure compound** existing as a solid.
- $$ \mathrm{CaO} $$ (calcium oxide) is also a **pure compound** in the solid state.
- $$ \mathrm{CO_2} $$ (carbon dioxide) is a **pure compound** in the gaseous state.

In this decomposition reaction, a single compound $$ \mathrm{CaCO_3} $$ (a pure chemical substance) breaks down into two other pure compounds, one solid ($$ \mathrm{CaO} $$) and one gas ($$ \mathrm{CO_2} $$).

---

**Step 2. Determining the Quantity of Particles in the Gaseous Product**

We are given that the volume of the collected gas is 6 liters and that one mole of any gas at standard conditions occupies 22.4 liters. (Since the students refer to “normal room conditions”, it is common in such problems to assume standard temperature and pressure conditions for simplicity.)

1. **Calculate the number of moles of $$ \mathrm{CO_2} $$:**

$$
   n = \frac{\text{Volume of gas}}{\text{Molar volume}} = \frac{6 \, \text{L}}{22.4 \, \text{L/mol}} \approx 0.268 \, \text{mol}
   $$

2. **Use Avogadro’s number to find the total number of molecules:**

Avogadro’s number is given as $$6.02 \times 10^{23}$$ particles per mole. Hence,

$$
   N = n \times (6.02 \times 10^{23} \, \text{particles/mol}) = 0.268 \times 6.02 \times 10^{23}
   $$

3. **Perform the multiplication:**

$$
   N \approx 1.61 \times 10^{23} \, \text{particles}
   $$

---

**Final Answer**

- The categories of substances are:  
  - $$ \mathrm{CaCO_3} $$ is a pure compound (solid),  
  - $$ \mathrm{CaO} $$ is a pure compound (solid),  
  - $$ \mathrm{CO_2} $$ is a pure compound (gas).

- The gaseous product ($$ \mathrm{CO_2} $$) contains approximately $$ 1.61 \times 10^{23} $$ particles.
**Categories of Substances Involved:** - $$ \mathrm{CaCO_3} $$ (solid) - $$ \mathrm{CaO} $$ (solid) - $$ \mathrm{CO_2} $$ (gas) **Quantity of Particles in the Gaseous Product:** Approximately $$ 1.61 \times 10^{23} $$ particles

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