Arrange in ascending order: \( -3,305 ; 3,15 ; 0,-3 ; 3,4 ;-3,35 \).

We are given the following five numbers written with a comma as the decimal separator: \[ -3,305;\quad 3,15;\quad 0,-3;\quad 3,4;\quad -3,35. \] Our first step is to interpret each number in a familiar decimal (point‐notation) format. In many countries the comma is used as the decimal separator. With that in mind, we interpret the numbers as follows: - \( -3,305 \) becomes \( -3.305 \) - \( 3,15 \) becomes \( 3.15 \) - \( 0,-3 \) is assumed to be a misplacement and is interpreted as \( -0.3 \) - \( 3,4 \) becomes \( 3.4 \) - \( -3,35 \) becomes \( -3.35 \) Now we have the set of numbers: \[ -3.305,\quad 3.15,\quad -0.3,\quad 3.4,\quad -3.35. \] We now arrange these numbers in ascending (increasing) order by comparing their values. ### Step 1. Compare the negative numbers There are three negative numbers: \( -3.305,\; -3.35,\; -0.3 \). - To compare \( -3.35 \) and \( -3.305 \), write them to the same number of decimal places: \[ -3.350\quad \text{and}\quad -3.305. \] Since \(-3.350 < -3.305\) (because \( -3.35 \) is further to the left on the number line), we have \[ -3.35 < -3.305. \] - The number \( -0.3 \) is much closer to zero than the other two negative numbers and therefore is larger than both. In summary, among the negative numbers: \[ -3.35 < -3.305 < -0.3. \] ### Step 2. The positive numbers The remaining numbers are positive: \[ 3.15 \quad \text{and} \quad 3.4. \] Clearly, \[ 3.15 < 3.4. \] ### Step 3. Combine the results We now combine the comparisons of the negative and positive numbers. The full sequence in ascending order is: \[ -3.35,\quad -3.305,\quad -0.3,\quad 3.15,\quad 3.4. \] In the original notation (using a comma as the decimal separator), the ordered list is: \[ -3,35;\quad -3,305;\quad 0,-3;\quad 3,15;\quad 3,4. \] Thus, the numbers arranged in ascending order are: \[ -3,35;\quad -3,305;\quad 0,-3;\quad 3,15;\quad 3,4. \]