Simplify. \( 4 \sqrt{28}+\sqrt{45}-\sqrt{112}-3 \sqrt{20} \) \( [?] \sqrt{[\quad]}-[\quad] \sqrt{[\square} \)

First, let's break down each term to simplify: 1. \( 4\sqrt{28} = 4\sqrt{4 \times 7} = 4 \times 2 \sqrt{7} = 8\sqrt{7} \) 2. \( \sqrt{45} = \sqrt{9 \times 5} = 3\sqrt{5} \) 3. \( \sqrt{112} = \sqrt{16 \times 7} = 4\sqrt{7} \) 4. \( 3\sqrt{20} = 3\sqrt{4 \times 5} = 3 \times 2\sqrt{5} = 6\sqrt{5} \) Now combine everything together: \[ 8\sqrt{7} + 3\sqrt{5} - 4\sqrt{7} - 6\sqrt{5} \] Combining like terms: \[ (8\sqrt{7} - 4\sqrt{7}) + (3\sqrt{5} - 6\sqrt{5}) = 4\sqrt{7} - 3\sqrt{5} \] Thus, the final simplified expression is: \[ 4\sqrt{7} - 3\sqrt{5} \] So, the answer is \( [4] \sqrt{[7]} - [3] \sqrt{[5]} \).