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Find \( Q_{1}, Q_{3} \), and IQR. (Round your answers to one decimal place as needed.) \[ \begin{array}{r}Q_{1}=\square \\ Q_{3}=\square \\ \text { IQR }=\square \\ \text { Check }\end{array} \]

Ask by Owen Peterson. in the United States
Mar 10,2025

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Cannot determine \( Q_1 \), \( Q_3 \), and IQR without the data set.

Solución

It appears that the data set for which we need to find \( Q_1 \), \( Q_3 \), and the IQR is not provided. Could you please supply the data so that we can work through the solution step by step?

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To find \( Q_{1} \), \( Q_{3} \), and the IQR (Interquartile Range), you need a dataset. However, I'll guide you through the general process assuming you have a numerical dataset. 1. **Organize your data**: Sort your dataset in ascending order. 2. **Find \( Q_{1} \)** (the first quartile): This is the median of the lower half of your data (not including the overall median if the number of data points is odd). 3. **Find \( Q_{3} \)** (the third quartile): This is the median of the upper half of your data. 4. **Calculate the IQR**: This is done by subtracting \( Q_{1} \) from \( Q_{3} \). As a fun example, if your data was: \( 1, 3, 4, 6, 8, 9, 10 \): - \( Q_{1} = 4 \) (median of \( 1, 3, 4, 6 \)) - \( Q_{3} = 9 \) (median of \( 8, 9, 10 \)) - \( IQR = 9 - 4 = 5 \) Fill in the blanks based on the values obtained from your specific dataset. Each \( Q \) value should be rounded to one decimal place! So, if your values are based on this example, the answers would look like: \[ \begin{array}{r} Q_{1}=4.0 \\ Q_{3}=9.0 \\ \text { IQR }=5.0 \\ \text { Check } \end{array} \] Make sure to work out the quartiles based on your data for the final answer!

preguntas relacionadas

Question 12(Mulliple Choice Warth 5 points) \[ (04.06 \mathrm{HC}) \] A researcher wants to test the claim that the proportion of juniors who watch television regularly is greater than the proportion of seniors who watch television regularly She finds that 56 of 70 randomly selected juniors and 47 of 85 randomly selected seniors report watching television regularly. Construct \( 95 \% \) confidence intervals for each population proportion. Which of the statemente gives the correct outcome of the research or's tert of the dalim? The \( 95 \% \) confidence interval for juniors is (706, 894), and the \( 95 \% \) confidence interval for seniors is ( 447,659 ). Since the intervals overlap, there is not enough evidence to say the proportion of juniors who watch television regularly may be higher than that of seniors. The \( 95 \% \) confidence interval for juniors is (721, 879), and the \( 95 \% \) confidence interval for seniors is (464, 642). Since the interval for juniors is higher than the interval for seniors, there is evidence to say the proportion of juniors who watch television regularly may be higher than that of seniors. The \( 95 \% \) confidence interval for juniors is ( 706,894 ), and the \( 95 \% \) confidence interval for seniors is ( 447,659 ). Since the interval for juniors is higher than the interval for seniors, there is evidence to say the proportion of juniors who watch television regularly may be higher than that of seniors. The \( 95 \% \) confidence interval for juniors is ( \( 721, .879 \) ), and the \( 95 \% \) confidence interval for seniors is (464, 642). Since the intervals overlap, there is not enough evidence to say the proportion of juniors who watch television regularly may be higher than that of seniors.

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