b. \( 10 C=B-2 A \quad \) for \( A \)

To solve the equation \( 10 C = B - 2A \) for \( A \), you first want to isolate \( A \). You can start by rearranging the equation: First, add \( 2A \) to both sides and subtract \( 10C \) from both sides: \[ 2A = B - 10C \] Now, divide both sides by 2 to solve for \( A \): \[ A = \frac{B - 10C}{2} \] And voila! You have expressed \( A \) in terms of \( B \) and \( C \). Now, wasn't that a puzzle? Just like in cooking, sometimes you just need to rearrange the ingredients a bit to make your final dish delightful! Keep practicing with similar equations, and you’ll become a pro at variable juggling!