Evaluar la función $$ f(x)=\frac{19-x}{-14+x} $$ En los valores indicados: $$ f(2)=\square $$ $$ f(-2)=\square $$ $$ f\left(\frac{1}{2}\right)=\square $$ $$ f(a)=\square $$ $$ f(a-1)=\square $$

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Evaluate the expression by following steps:
- step0: Evaluate:
  $$\frac{19-x}{-14+x}$$
- step1: Substitute:
  $$\frac{19-\left(-2\right)}{-14-2}$$
- step2: Add the numbers:
  $$\frac{21}{-14-2}$$
- step3: Subtract the numbers:
  $$\frac{21}{-16}$$
- step4: Rewrite the fraction:
  $$-\frac{21}{16}$$
Substitute $$ x=a-1 $$ into the expression $$ \frac{19-x}{-14+x} $$.
Evaluate the expression by following steps:
- step0: Evaluate:
  $$\frac{19-x}{-14+x}$$
- step1: Substitute:
  $$\frac{19-\left(a-1\right)}{-14+a-1}$$
- step2: Calculate:
  $$\frac{19-a+1}{-14+a-1}$$
- step3: Add the numbers:
  $$\frac{20-a}{-14+a-1}$$
- step4: Subtract the numbers:
  $$\frac{20-a}{-15+a}$$
Substitute $$ x=2 $$ into the expression $$ \frac{19-x}{-14+x} $$.
Evaluate the expression by following steps:
- step0: Evaluate:
  $$\frac{19-x}{-14+x}$$
- step1: Substitute:
  $$\frac{19-2}{-14+2}$$
- step2: Subtract the numbers:
  $$\frac{17}{-14+2}$$
- step3: Add the numbers:
  $$\frac{17}{-12}$$
- step4: Rewrite the fraction:
  $$-\frac{17}{12}$$
Substitute $$ x=\frac{1}{2} $$ into the expression $$ \frac{19-x}{-14+x} $$.
Evaluate the expression by following steps:
- step0: Evaluate:
  $$\frac{19-x}{-14+x}$$
- step1: Substitute:
  $$\frac{19-\frac{1}{2}}{-14+\frac{1}{2}}$$
- step2: Subtract the numbers:
  $$\frac{\frac{37}{2}}{-14+\frac{1}{2}}$$
- step3: Add the numbers:
  $$\frac{\frac{37}{2}}{-\frac{27}{2}}$$
- step4: Multiply by the reciprocal:
  $$\frac{37}{2}\left(-\frac{2}{27}\right)$$
- step5: Multiply the numbers:
  $$-\frac{37}{2}\times \frac{2}{27}$$
- step6: Reduce the numbers:
  $$-37\times \frac{1}{27}$$
- step7: Multiply:
  $$-\frac{37}{27}$$
Substitute $$ x=a $$ into the expression $$ \frac{19-x}{-14+x} $$.
Evaluate the expression by following steps:
- step0: Evaluate:
  $$\frac{19-x}{-14+x}$$
- step1: Substitute:
  $$\frac{19-a}{-14+a}$$
Vamos a evaluar la función $$ f(x)=\frac{19-x}{-14+x} $$ en los valores indicados:

1. **Para $$ f(2) $$**:
   $$
   f(2) = \frac{19-2}{-14+2} = \frac{17}{-12} = -\frac{17}{12}
   $$

2. **Para $$ f(-2) $$**:
   $$
   f(-2) = \frac{19-(-2)}{-14+(-2)} = \frac{19+2}{-14-2} = \frac{21}{-16} = -\frac{21}{16}
   $$

3. **Para $$ f\left(\frac{1}{2}\right) $$**:
   $$
   f\left(\frac{1}{2}\right) = \frac{19-\frac{1}{2}}{-14+\frac{1}{2}} = \frac{19-\frac{1}{2}}{-14+\frac{1}{2}} = \frac{\frac{38}{2}-\frac{1}{2}}{-\frac{28}{2}+\frac{1}{2}} = \frac{\frac{37}{2}}{-\frac{27}{2}} = -\frac{37}{27}
   $$

4. **Para $$ f(a) $$**:
   $$
   f(a) = \frac{19-a}{-14+a}
   $$

5. **Para $$ f(a-1) $$**:
   $$
   f(a-1) = \frac{19-(a-1)}{-14+(a-1)} = \frac{19-a+1}{-14+a-1} = \frac{20-a}{-15+a}
   $$

Resumiendo los resultados:
- $$ f(2) = -\frac{17}{12} $$
- $$ f(-2) = -\frac{21}{16} $$
- $$ f\left(\frac{1}{2}\right) = -\frac{37}{27} $$
- $$ f(a) = \frac{19-a}{-14+a} $$
- $$ f(a-1) = \frac{20-a}{-15+a} $$
- $$ f(2) = -\frac{17}{12} $$ - $$ f(-2) = -\frac{21}{16} $$ - $$ f\left(\frac{1}{2}\right) = -\frac{37}{27} $$ - $$ f(a) = \frac{19-a}{-14+a} $$ - $$ f(a-1) = \frac{20-a}{-15+a} $$

Evaluar la función \( f(x)=\frac{19-x}{-14+x} \) En los valores indicados: \( f(2)=\square \) \( f(-2)=\square \) \( f\left(\frac{1}{2}\right)=\square \) \( f(a)=\square \) \( f(a-1)=\square \)

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