(a) Find the following side lengths for the net. \( A=15 \mathrm{yd} \) \( B=2 \mathrm{yd} \) \( C=8 \mathrm{yd} \) \( D=17 \mid \mathrm{yd} \) (b) Use the net to find the surface area of the prism. \( \square \mathrm{yd}{ }^{2} \)
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To find the side lengths for the net, let’s first identify the dimensions based on the given measurements. Each side length corresponds to the edges that make up the rectangular faces of the prism. Thus, you would have: - Length of one rectangle: \( A = 15 \, \text{yd} \) - Width of another rectangle: \( B = 2 \, \text{yd} \) - Height of one rectangle: \( C = 8 \, \text{yd} \) - Base width of the largest rectangle: \( D = 17 \, \text{yd} \) Now that we have these dimensions, we can proceed to calculate the surface area of the prism. To calculate the surface area, you generally add the areas of all the faces. Assuming this is a rectangular prism, the formula is: \[ \text{Surface Area} = 2(lb + lh + bh) \] Substituting the respective values, if \( l = 15 \, \text{yd}, \, b = 17 \, \text{yd}, \, h = 8 \, \text{yd} \): \[ \text{SA} = 2(15 \times 17 + 15 \times 8 + 17 \times 8) \] Calculating: \[ 15 \times 17 = 255 \] \[ 15 \times 8 = 120 \] \[ 17 \times 8 = 136 \] Adding these: \[ 255 + 120 + 136 = 511 \] Now multiplying by 2: \[ \text{Surface Area} = 2 \times 511 = 1022 \, \text{yd}^2 \] So, the surface area of the prism is \( 1022 \, \text{yd}^2 \).
