Pregunta
\begin{tabular}{l|l}\hline 10. Monica really loved the strawberry Blow Pops \\ She was determined to go as long as she could without \\ crunching it. She put it in her mouth at \( 1: 46 \) but she \\ started crunching it at \( 2: 13 \). How long did she go \\ without crunching it? \end{tabular}
Ask by Brewer Johnston. in the United States
Mar 10,2025
Solución de inteligencia artificial de Upstudy
Respuesta verificada por el tutor
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Monica went without crunching the Blow Pop for 27 minutes.
Solución
1. Convert the times to minutes past midnight:
- For \(1{:}46\): \(1 \times 60 + 46 = 60 + 46 = 106\) minutes.
- For \(2{:}13\): \(2 \times 60 + 13 = 120 + 13 = 133\) minutes.
2. Find the difference:
\[
\text{Time difference} = 133 - 106 = 27 \text{ minutes.}
\]
Monica went without crunching the Blow Pop for \(27\) minutes.
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Simplifique esta solución Extra Insights
Monica put the strawberry Blow Pop in her mouth at \( 1:46 \) and started crunching it at \( 2:13 \). To find out how long she went without crunching it, we need to calculate the difference between these two times. First, we convert the times into minutes past midnight: - \( 1:46 \) is 106 minutes - \( 2:13 \) is 133 minutes Now, we subtract: \[ 133 \text{ minutes} - 106 \text{ minutes} = 27 \text{ minutes} \] So, Monica went for **27 minutes** without crunching her Blow Pop!
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