29.) \( 15 m=45 \) 36.) \( 2 m=124 \) 30.) \( 7 d=56 \) 37.) \( 14 r=42 \) 31.) \( 21 x=84 \) 38.) \( \mathbf{2 9 t}=77 \) 32.) \( 9 y=63 \) 39.) \( 9 x=143 \) 33.) \( \frac{2}{7} x=8 \) 40.) \( \frac{1}{2} v=10 \) 34.) \( \frac{3}{5} z=12 \) 41.) \( \frac{2}{3} c=8 \) 35.) \( \frac{4}{6} z=7^{1 / 3} \) 42.) \( \frac{3}{4} c=51 / 4 \)

We have a list of separate equations. (Even though some of the same letters appear more than once, each equation is to be solved on its own.) One acceptable set of solutions is as follows: 29.) 15m = 45   Divide both sides by 15: m = 45⁄15 = 3 30.) 7d = 56   Divide by 7: d = 56⁄7 = 8 31.) 21x = 84   Divide by 21: x = 84⁄21 = 4 32.) 9y = 63   Divide by 9: y = 63⁄9 = 7 33.) (2⁄7)x = 8   Multiply both sides by 7⁄2: x = 8×(7⁄2) = 56⁄2 = 28 34.) (3⁄5)z = 12   Multiply both sides by 5⁄3: z = 12×(5⁄3) = 60⁄3 = 20 35.) (4⁄6)z = 7^(1⁄3)   Note that 4⁄6 simplifies to 2⁄3. Then: (2⁄3)z = 7^(1⁄3)   Multiply both sides by 3⁄2: z = 7^(1⁄3)×(3⁄2) = (3⁄2)·7^(1⁄3) 36.) 2m = 124   Divide both sides by 2: m = 124⁄2 = 62 37.) 14r = 42   Divide by 14: r = 42⁄14 = 3 38.) 29t = 77   Divide by 29: t = 77⁄29   (This fraction does not simplify further.) 39.) 9x = 143   Divide by 9: x = 143⁄9   (Note: 143 factors as 11×13 and does not cancel with 9.) 40.) (1⁄2)v = 10   Multiply both sides by 2: v = 10×2 = 20 41.) (2⁄3)c = 8   Multiply by 3⁄2: c = 8×(3⁄2) = 24⁄2 = 12 42.) (3⁄4)c = 51⁄4   Multiply both sides by 4⁄3: c = (51⁄4)×(4⁄3) = 51⁄3 = 17 Each equation is solved independently, so even though the same variable symbol appears more than once, you have to use the appropriate answer for each separate problem.