7. $$ y=5 x-2 $$ $$ (0,-),(3, \ldots),(-9, \ldots) $$

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Certainly! Let's evaluate the linear equation $$ y = 5x - 2 $$ for the given values of $$ x $$ and complete the coordinate points.

### Given:
$$
y = 5x - 2
$$

### Points to Complete:
1. $$ (0, \, \_ ) $$
2. $$ (3, \, \_ ) $$
3. $$ (-9, \, \_ ) $$

### Calculations:

1. **For $$ x = 0 $$:**
   $$
   y = 5(0) - 2 = 0 - 2 = -2
   $$
   **Point:** $$ (0, \mathbf{-2}) $$

2. **For $$ x = 3 $$:**
   $$
   y = 5(3) - 2 = 15 - 2 = 13
   $$
   **Point:** $$ (3, \mathbf{13}) $$

3. **For $$ x = -9 $$:**
   $$
   y = 5(-9) - 2 = -45 - 2 = -47
   $$
   **Point:** $$ (-9, \mathbf{-47}) $$

### Completed Coordinate Points:
$$
(0, \mathbf{-2}), \quad (3, \mathbf{13}), \quad (-9, \mathbf{-47})
$$

### Summary:
By substituting the given $$ x $$-values into the equation $$ y = 5x - 2 $$, we've determined the corresponding $$ y $$-values and completed the coordinate points as shown above.
The completed coordinate points are: - $$ (0, -2) $$ - $$ (3, 13) $$ - $$ (-9, -47) $$

7. \( y=5 x-2 \) \( (0,-),(3, \ldots),(-9, \ldots) \)

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