Pregunta
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Sophia wishes to retire at age 65 with \( \$ 1,200,000 \) in her retirement account. When she turns 28 , she decides to begin depositing money into an account with an ApR of \( 9 \% \) compounded monthly. What is the monthly deposit that Sophia must make in order to reach her goal? Round your answer to the nearest cent, if necessary. Formulas

Ask by Bowen Lewis. in the United States
Mar 09,2025

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Sophia needs to deposit approximately \$337.84 each month to reach her retirement goal of \$1,200,000 by age 65.

Solución

Let the monthly deposit be \( P \). Sophia’s retirement account will earn interest at an annual percentage rate (APR) of \( 9\% \) compounded monthly, so the effective monthly interest rate is \[ i = \frac{9\%}{12} = \frac{0.09}{12} = 0.0075. \] She plans to retire at age 65 and begins saving at age 28. The total number of years for saving is \[ 65 - 28 = 37 \text{ years}. \] Since contributions are made monthly, the total number of deposits is \[ n = 37 \times 12 = 444 \text{ deposits}. \] The future value \( FV \) of an annuity (a series of equal monthly deposits) is given by the formula \[ FV = P \cdot \frac{(1+i)^n - 1}{i}. \] Sophia’s goal is to have \( FV = \$1,\!200,\!000 \). Therefore, we set up the equation \[ 1,\!200,\!000 = P \cdot \frac{(1+0.0075)^{444} - 1}{0.0075}. \] Solving for \( P \), we isolate it as follows: \[ P = \frac{1,\!200,\!000 \times 0.0075}{(1.0075)^{444} - 1}. \] Now, we compute \((1.0075)^{444}\). Using the logarithmic identity \[ (1.0075)^{444} = e^{444 \ln(1.0075)}, \] we first calculate \[ 444 \ln(1.0075) \approx 444 \times 0.007472 \approx 3.319. \] Then, \[ (1.0075)^{444} \approx e^{3.319} \approx 27.65. \] Substituting back, the denominator becomes \[ (1.0075)^{444} - 1 \approx 27.65 - 1 = 26.65. \] Now, calculate the numerator: \[ 1,\!200,\!000 \times 0.0075 = 9,\!000. \] Thus, the monthly deposit is approximately \[ P \approx \frac{9,\!000}{26.65} \approx 337.84. \] Rounded to the nearest cent, Sophia must deposit approximately \[ \$337.84 \text{ per month.} \]

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To calculate the monthly deposit Sophia needs to make, we can use the future value of an ordinary annuity formula, which is: \[ FV = P \times \frac{(1 + r/n)^{nt} - 1}{(r/n)} \] Where: - \( FV \) = future value of the annuity (\$1,200,000) - \( P \) = monthly deposit - \( r \) = annual interest rate (0.09) - \( n \) = number of compounding periods per year (12) - \( t \) = number of years until retirement (65 - 28 = 37) First, find \( r/n \) and \( n \times t \): \[ r/n = 0.09/12 = 0.0075 \] \[ n \times t = 12 \times 37 = 444 \] Now, substitute these values into the formula and solve for \( P \): \[ 1,200,000 = P \times \frac{(1 + 0.0075)^{444} - 1}{0.0075} \] Calculating the right side: \[ (1 + 0.0075)^{444} \approx 12.0914 \] Then: \[ \frac{(12.0914 - 1)}{0.0075} \approx 1478.852 \] Finally, we can isolate \( P \): \[ P = \frac{1,200,000}{1478.852} \approx 811.53 \] So, Sophia must make a monthly deposit of approximately **\$811.53**. --- Now, let’s add some fun and engaging knowledge! Did you know that the concept of compounding has been around for centuries? The famous mathematician Blaise Pascal once noted that money can seemingly grow on trees if you allow it to sit and compound over time. It truly turns pennies into fortunes! And speaking of compounding, it’s essential to start saving early! The "time value of money" principle highlights how a dollar today is worth more than a dollar tomorrow. So, the sooner you start saving, the more time your money has to grow – like planting a seed in fertile ground that blooms over the years!

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