3.3 Long Division of Polynomials In Exercises 51-56, use long division to divide. 51. \( \frac{30 x^{2}-3 x+8}{5 x-3} \) 52. \( \frac{4 x+7}{3 x-2} \)
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To divide \(30x^2 - 3x + 8\) by \(5x - 3\) using long division, start by determining how many times \(5x\) goes into the leading term \(30x^2\). This equals \(6x\), so multiply \(5x - 3\) by \(6x\) to get \(30x^2 - 18x\). Subtract this from \(30x^2 - 3x + 8\), giving \(15x + 8\). Next, divide \(15x\) by \(5x\) to get \(3\), multiply \(5x - 3\) by \(3\) to get \(15x - 9\), and subtract, yielding \(17\). Thus, the final result is \(6x + 3 + \frac{17}{5x - 3}\). Now, for the division of \(4x + 7\) by \(3x - 2\): Start with the leading term, \(4x\), and divide by \(3x\), which gives \(\frac{4}{3}\). Multiply \(3x - 2\) by \(\frac{4}{3}\) resulting in \(4x - \frac{8}{3}\). Now, subtract this from \(4x + 7\). You state \(7 - \left(-\frac{8}{3}\right) = \frac{21}{3} + \frac{8}{3} = \frac{29}{3}\). The complete answer is \(\frac{4}{3} + \frac{\frac{29}{3}}{3x - 2}\) or \(\frac{4}{3} + \frac{29}{9x - 6}\).
