UESTION 1 [11] 1.1 Given: $$ \sqrt{9+25} ; \pi-4 ; \sqrt[3]{-27} ; \frac{2}{3} ; \frac{18}{2} ; \sqrt{-27} $$ From the list given above, write down: 1.1.1 A natural number. 1.1.2 A negative irrational number. 1.1.3 A non-real number. 1.1.4 A rational number which is not an integer.

Question

UpStudy AI · Accepted Answer

1.1.1 To find a natural number, we look for a positive integer. Notice that

$$
\frac{18}{2} = 9
$$

and $$9$$ is a natural number.

1.1.2 For a negative irrational number, we identify

$$
\pi - 4 \approx 3.14 - 4 \approx -0.86.
$$

Since $$\pi$$ is irrational, $$\pi - 4$$ is also irrational and negative.

1.1.3 A non-real number has a complex component (involving the square root of a negative number). Here, we have

$$
\sqrt{-27},
$$

which is non-real.

1.1.4 A rational number that is not an integer is given by the fraction

$$
\frac{2}{3},
$$

since it cannot be simplified to an integer.
1.1.1 Natural number: 9 1.1.2 Negative irrational number: π - 4 1.1.3 Non-real number: √(-27) 1.1.4 Rational number that is not an integer: 2/3

UESTION 1 [11] 1.1 Given: \( \sqrt{9+25} ; \pi-4 ; \sqrt[3]{-27} ; \frac{2}{3} ; \frac{18}{2} ; \sqrt{-27} \) From the list given above, write down: 1.1.1 A natural number. 1.1.2 A negative irrational number. 1.1.3 A non-real number. 1.1.4 A rational number which is not an integer.

Solución de inteligencia artificial de Upstudy

Responder

Solución

Beyond the Answer

preguntas relacionadas

Latest Pre Algebra Questions