The trinomial \( x^{2}+7 x-18 \) factors into (Factor completely.)

To factor the trinomial \( x^{2}+7x-18 \), we look for two numbers that multiply to \(-18\) (the constant term) and add up to \(7\) (the coefficient of \(x\)). Those two numbers are \(9\) and \(-2\), since \(9 \times -2 = -18\) and \(9 + (-2) = 7\). Thus, we can write the factored form as \( (x + 9)(x - 2) \). So, the complete factorization of \( x^{2}+7x-18 \) is \( (x + 9)(x - 2) \).