Write the domain of the function in interval notation．Write numbers as integers or simplified fractions． $$ f(x)=\frac{x^{2}-25}{x-5} $$ The domain of $$ f(x) $$ is $$ \square $$. （ロ，ロ）［ロ，ロ］（ロ，ロ］

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To find the domain of the function

$$
f(x) = \frac{x^{2} - 25}{x - 5},
$$

we need to identify any values of $$ x $$ that would make the function undefined. The function is undefined when the denominator is equal to zero.

1. **Set the denominator to zero:**
   $$
   x - 5 = 0
   $$
   Solving this gives:
   $$
   x = 5.
   $$

2. **Identify the domain:**
   The function is defined for all real numbers except $$ x = 5 $$. Therefore, the domain in interval notation excludes this point.

3. **Express the domain in interval notation:**
   The domain can be expressed as:
   $$
   (-\infty, 5) \cup (5, \infty).
   $$

Thus, the domain of $$ f(x) $$ is

$$
(-\infty, 5) \cup (5, \infty).
$$
The domain of $$ f(x) $$ is $$ (-\infty, 5) \cup (5, \infty) $$.

Write the domain of the function in interval notation．Write numbers as integers or simplified fractions． \[ f(x)=\frac{x^{2}-25}{x-5} \] The domain of \( f(x) \) is \( \square \). （ロ，ロ）［ロ，ロ］（ロ，ロ］

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