Evaluate the summation below. \[ 3 \sum_{d=0}^{3}(-d-1) \]
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The Deep Dive
To evaluate the summation \[ 3 \sum_{d=0}^{3}(-d-1), \] we first calculate the inner summation \( \sum_{d=0}^{3}(-d-1) \). We can break this down by calculating \(-d-1\) for each value of \(d\) from 0 to 3: - For \(d = 0\): \[ -0 - 1 = -1. \] - For \(d = 1\): \[ -1 - 1 = -2. \] - For \(d = 2\): \[ -2 - 1 = -3. \] - For \(d = 3\): \[ -3 - 1 = -4. \] Now, we can compute the sum: \[ \sum_{d=0}^{3}(-d-1) = -1 + (-2) + (-3) + (-4). \] Calculating this gives: \[ -1 - 2 - 3 - 4 = -10. \] Next, we multiply this result by 3: \[ 3 \sum_{d=0}^{3}(-d-1) = 3 \times (-10) = -30. \] Thus, the value of the original summation is \[ \boxed{-30}. \]
