\( \begin{array}{l}\text { Activity } 1 ; \text { Try It } \\ \text { Find the first quartile }\left(Q_{1}\right) \text {, second quartile }\left(Q_{2}\right) \text {, and the third quartile } \\ \left(Q_{3}\right) \text {, given the scores of } 10 \text { students in their Mathematics activity using } \\ \text { Mendenhall and Sincich Method. } \\ 4\end{array} \quad 9 \quad 7 \)

To find the first quartile \(Q_1\), second quartile \(Q_2\) (which is the median), and third quartile \(Q_3\) using the Mendenhall and Sincich method, we will follow these steps: 1. **Organize the Data**: First, we need to arrange the scores in ascending order. 2. **Calculate Quartiles**: - \(Q_1\) is the median of the first half of the data. - \(Q_2\) is the median of the entire dataset. - \(Q_3\) is the median of the second half of the data. ### Step 1: Organize the Data The given scores are: \(4, 9, 7\). Let's arrange these scores in ascending order: - Ordered scores: \(4, 7, 9\) ### Step 2: Calculate Quartiles Since we only have 3 scores, we can calculate the quartiles directly. 1. **Calculate \(Q_2\)** (Median): - The median \(Q_2\) is the middle value of the ordered dataset. - For 3 scores, the median is the second score. - Thus, \(Q_2 = 7\). 2. **Calculate \(Q_1\)** (First Quartile): - \(Q_1\) is the median of the first half of the data. Since we have only one score in the first half (which is \(4\)), \(Q_1 = 4\). 3. **Calculate \(Q_3\)** (Third Quartile): - \(Q_3\) is the median of the second half of the data. Since we have only one score in the second half (which is \(9\)), \(Q_3 = 9\). ### Summary of Results - \(Q_1 = 4\) - \(Q_2 = 7\) - \(Q_3 = 9\) Thus, the first quartile \(Q_1\) is \(4\), the second quartile \(Q_2\) is \(7\), and the third quartile \(Q_3\) is \(9\).