Please do the following calculation. You need to simplify your answer and rewrite any improper fractions as a mixed number or integer. \( 3 \frac{1}{6}+2 \frac{3}{4}= \)

First, convert the mixed numbers to improper fractions. For \( 3 \frac{1}{6} \), multiply \( 3 \times 6 + 1 = 19 \), so it becomes \( \frac{19}{6} \). For \( 2 \frac{3}{4} \), multiply \( 2 \times 4 + 3 = 11 \), so it becomes \( \frac{11}{4} \). Now, find a common denominator, which is 12: - Convert \( \frac{19}{6} \) to \( \frac{38}{12} \) (multiply numerator and denominator by 2). - Convert \( \frac{11}{4} \) to \( \frac{33}{12} \) (multiply numerator and denominator by 3). Now, add the fractions: \[ \frac{38}{12} + \frac{33}{12} = \frac{71}{12} \] Finally, convert \( \frac{71}{12} \) to a mixed number: \( 5 \frac{11}{12} \). So, \( 3 \frac{1}{6} + 2 \frac{3}{4} = 5 \frac{11}{12} \).