Find the domain of the function. $$ f(x)=\frac{6}{x^{2}+16}-\frac{8}{x^{2}-4} $$ What is the domain of $$ f $$ ? (Type your answer in interval notation.)

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The domain of $$ f(x)=\frac{6}{x^{2}+16}-\frac{8}{x^{2}-4} $$ is determined by identifying the values of $$ x $$ that make any denominator equal to zero.

1. For the first term, the denominator is $$ x^{2}+16 $$. Since $$ x^{2} \geq 0 $$ for all $$ x $$, we have
   $$
   x^{2}+16 \geq 16 > 0.
   $$
   There are no restrictions from this term.

2. For the second term, the denominator is $$ x^{2}-4 $$. Set it equal to zero to find the critical points:
   $$
   x^{2}-4 = 0 \quad \Rightarrow \quad x^{2} = 4 \quad \Rightarrow \quad x = 2 \quad \text{or} \quad x = -2.
   $$
   The denominator is zero when $$ x=2 $$ or $$ x=-2 $$.

Thus, $$ x $$ cannot be $$ 2 $$ or $$ -2 $$. There are no other restrictions.

So, the domain of $$ f $$ in interval notation is:
$$
(-\infty,-2) \cup (-2,2) \cup (2,\infty).
$$
The domain of $$ f(x) $$ is all real numbers except $$ x = -2 $$ and $$ x = 2 $$. In interval notation, this is $$ (-\infty, -2) \cup (-2, 2) \cup (2, \infty) $$.

Find the domain of the function.

What is the domain of ?
(Type your answer in interval notation.)

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Find the domain of the function. What is the domain of ? (Type your answer in interval notation.)