Simplify. \( \frac{\sin x}{1+\cos x}+\frac{1+\cos x}{\sin x} \) \( [?] \)
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To simplify the expression \( \frac{\sin x}{1+\cos x}+\frac{1+\cos x}{\sin x} \), we can start by finding a common denominator. The common denominator is \( \sin x (1 + \cos x) \). Rewriting each fraction: \[ \frac{\sin x \cdot \sin x}{\sin x (1+\cos x)} + \frac{(1+\cos x)(1+\cos x)}{\sin x (1+\cos x)} \] This gives us: \[ \frac{\sin^2 x + (1 + \cos x)^2}{\sin x (1+\cos x)} \] Now simplifying the numerator: \[ \sin^2 x + (1 + 2\cos x + \cos^2 x) = \sin^2 x + 1 + 2\cos x + \cos^2 x \] Using the Pythagorean identity \( \sin^2 x + \cos^2 x = 1 \): \[ 1 + 1 + 2\cos x = 2 + 2\cos x \] Thus, the expression becomes: \[ \frac{2(1 + \cos x)}{\sin x (1 + \cos x)} \] Assuming \( 1 + \cos x \neq 0 \), we can cancel \( 1 + \cos x \): \[ \frac{2}{\sin x} = 2 \csc x \] Therefore, the simplified expression is: \[ 2 \csc x \]
