\( \sin x < \cos x \)

To solve \( \sin x < \cos x \), we can rearrange it to \( \tan x < 1 \), which means that the angles we are interested in lie in the range where the sine function is less than the cosine function. This can be true in the first quadrant (where both sine and cosine are positive) and in the fourth quadrant (where sine is positive, and cosine is negative), essentially between \( 0 \) to \( \frac{\pi}{4} \) and \( \frac{5\pi}{4} \) to \( 2\pi \). Now let’s make this practical! Think of it in real life: if you're on a hike and you're standing at a point where the incline you're walking up is less steep than the angle to the horizontal line (like a ski slope), the sine (height over hypotenuse) will be less than the cosine (base over hypotenuse) until you reach that \( 45^\circ \) mark. Keep pushing towards the summit!