\( \begin{array}{ll}\frac{1}{5} \times 30= & \text { c } \frac{1}{3} \text { of } 27= \\ \frac{4}{5} \times 30= & \text { f } \frac{2}{3} \times 27=\end{array} \)

To solve these expressions, let's break them down step by step: First, for \( \frac{1}{5} \times 30 \): Multiply \( 30 \) by \( \frac{1}{5} \): \[ \frac{1}{5} \times 30 = 6 \] So, \( c = 6 \). Next, for \( \frac{1}{3} \text{ of } 27 \): Multiply \( 27 \) by \( \frac{1}{3} \): \[ \frac{1}{3} \times 27 = 9 \] Therefore, \( c = 6 \) and \( \frac{1}{3} \text{ of } 27 = 9 \). Now for \( \frac{4}{5} \times 30 \): Multiply \( 30 \) by \( \frac{4}{5} \): \[ \frac{4}{5} \times 30 = 24 \] Thus, \( f = 24 \). Finally, for \( \frac{2}{3} \times 27 \): Multiply \( 27 \) by \( \frac{2}{3} \): \[ \frac{2}{3} \times 27 = 18 \] So, \( f = 24 \) and \( \frac{2}{3} \times 27 = 18 \). In summary, the answers are: \( c = 6, \text{ and } 9 \) \( f = 24, \text{ and } 18 \)