\begin{tabular}{l} Employee is a base class and HourlyWorker is a \\ derived class, with a redefined non-virtual print \\ function. Given the following statements, will \\ the output of the two print function calls be \\ identical? \\ HourlyWorker h; \\ Employee *ePtr = \&h; \\ ePtr->print(); \\ ePtr->Employee::print(); \\ Yes. \\ Yes, if print is a static function. \\ It would depend on the implementation of the \\ print function. \\ No. \\ \hline\end{tabular}

The outcome of the two print function calls will not be identical because the first call, `ePtr->print();`, invokes the overridden `print` function in the `HourlyWorker` class. Since `print` is a non-virtual function in the base `Employee` class, C++ will use static binding for this call. Therefore, the second call, `ePtr->Employee::print();`, explicitly calls the base class's print function, leading to different outputs. Understanding function binding in C++ is crucial! In this case, the concept of polymorphism highlights the power of virtual functions. If `print` were declared as a virtual function, both calls would result in the same output. So remember, when dealing with inheritance, the distinction between static and dynamic binding can completely change your program's behavior!